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If $\tan \theta=2$ and $\theta$ lies in the third quadrant, then the value of $\sec \theta$ is
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The correct answer is:
$-\sqrt{5}$
$\sec ^{2} \theta=1+(2)^{2}=5$
$\therefore \sec \theta=-\sqrt{5}$ $\quad\quad\left[\because \theta\right.$ lies in $3^{\text {nd }}$ quadrant. $]$
$\therefore \sec \theta=-\sqrt{5}$ $\quad\quad\left[\because \theta\right.$ lies in $3^{\text {nd }}$ quadrant. $]$
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