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Question: Answered & Verified by Expert
If $\tan \left(\frac{B-C}{2}\right)=x \cot \left(\frac{A}{2}\right)$, find the value of $x$
MathematicsProperties of TrianglesJEE Main
Options:
  • A $\frac{c-a}{c+a}$
  • B $\frac{a-b}{a+b}$
  • C $\frac{b-c}{b+c}$
  • D None
Solution:
1714 Upvotes Verified Answer
The correct answer is: $\frac{b-c}{b+c}$
By the formulae
$\tan \left(\frac{B-C}{2}\right)=\frac{b-c}{b+c} \cot \left(\frac{A}{2}\right)$

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