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If the angle between the vector $\vec{A}$ and $(\vec{B} \times \vec{A}) \cdot \vec{A}$ is $\theta$, the value of the product $(\vec{B} \times \vec{A}) \cdot \vec{A}$ is equal to:
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The correct answer is:
zero
$(\vec{B} \times \vec{B}) \vec{A}=(B A \sin \theta)(\vec{n} \cdot \vec{A})=0$
Since $n$ is perpendicular to both $\vec{A}$ and $\vec{B}$.
Since $n$ is perpendicular to both $\vec{A}$ and $\vec{B}$.
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