Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
If the area bounded by the curves x2+y24, x+y2, and y1 is 2πK-K2-12 sq. units, then the value of K is equal to
MathematicsArea Under CurvesJEE Main
Solution:
1740 Upvotes Verified Answer
The correct answer is: 3

The required area is A=124-y2dy-AreaAPQ
A=y4-y22+42sin-1y212-12×1×1
A=0+2sin-11-32-2sin-112-12
=π-32-π3-12
=2π3-32-12 sq. units

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.