If the area bounded by the curves x , y | x 2 - y + 1 ≥ 0 and x , y | x + y - 3 ≥ 0 is k square units, then the value of 3 k is equal to

Question

If the area bounded by the curves x , y | x 2 - y + 1 ≥ 0 and x , y | x + y - 3 ≥ 0 is k square units, then the value of 3 k is equal to, 27, 9, 9 2, 27 2

MARKS App · Accepted Answer

The required area is k sq. units ⇒ k = ∫ - 2 1 3 - x - x 2 + 1 d x = 2 x - x 2 2 - x 3 3 - 2 1 ⇒ k = 9 2 ⇒ 3 k = 27 2

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