If the area bounded by y = x 2 - 4 x + 3 and the x -axis from x = 1 to x = 3 is p q (where, p & q are coprime), then the value of p + q is

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Question: Answered & Verified by Expert

If the area bounded by

y = |{|x|}^{2} - 4 |x + 3||

and the

x

-axis from

x = 1

to

x = 3

is

\frac{p}{q}

(where,

p

&

q

are coprime), then the value of

p + q

is

MathematicsArea Under CurvesJEE Main

Solution:

1394 Upvotes Verified Answer

The correct answer is: 97

Area

= |\int_{1}^{3} (4 x - x^{2} + 12) d x|

= \frac{94}{3}

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