Search any question & find its solution
Question:
Answered & Verified by Expert
If the axes are shifted to the point $(1,-2)$ with out solution, then the equation $2 x^{2}+y^{2}-4 x+4 y=0$ becomes
Options:
Solution:
1834 Upvotes
Verified Answer
The correct answer is:
$2 X^{2}+Y^{2}=6$
Substituting $x=X+1$ and $y=Y-2$ in given equation, we get
$$
\begin{array}{l}
2(X+1)^{2}+(Y-2)^{2}-4(X+1)+4(Y-2)=0 \\
\Rightarrow 2 X^{2}+Y^{2}=6
\end{array}
$$
$$
\begin{array}{l}
2(X+1)^{2}+(Y-2)^{2}-4(X+1)+4(Y-2)=0 \\
\Rightarrow 2 X^{2}+Y^{2}=6
\end{array}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.