If the binding energy per nucleon in 3 L i 7 and 2 He 4 nuclei are respectively 5 . 60 MeV and 7 . 06 MeV , then the energy of the proton in the reaction 3 L i + p → 2 2 H e 4 is

Question

If the binding energy per nucleon in 3 L i 7 and 2 He 4 nuclei are respectively 5 . 60 MeV and 7 . 06 MeV , then the energy of the proton in the reaction 3 L i + p → 2 2 H e 4 is, 19 . 6 MeV, 2 . 4 MeV, 8 . 4 MeV, 17 . 3 MeV

MARKS App · Accepted Answer

Applying principle of energy conservation. Energy of proton = total BE of 2 α - energy of L i 7 = 8 × 7.06 - 7 × 5.6 = 56.48 - 39.2 = 17.28 M e V

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