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If the center, one of the foci and semi-major axis of an ellipse be $(0,0),(0,3)$ and 5 then its equation is
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The correct answer is:
$\frac{x^2}{16}+\frac{y^2}{25}=1$
Centre $(0,0)$, focus $(0,3), b=5$
Focus $(0,3) \Rightarrow b e=3 \Rightarrow e=3 / 5 \Rightarrow a=b \sqrt{1-e^2}=4$
Hence the required equation is $\frac{x^2}{16}+\frac{y^2}{25}=1$.
Focus $(0,3) \Rightarrow b e=3 \Rightarrow e=3 / 5 \Rightarrow a=b \sqrt{1-e^2}=4$
Hence the required equation is $\frac{x^2}{16}+\frac{y^2}{25}=1$.
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