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If the charge on the capacitor is increased by $2 \mathrm{C}$. The energy stored in it increase by $21 \%$. Total original charge on the capacitor is
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Verified Answer
The correct answer is:
20 C
$$
\begin{aligned}
& U=\frac{q^2}{2 \mathrm{C}} \\
& 1.21 U=\frac{(q+2)^2}{2 \mathrm{C}}
\end{aligned}
$$
By solving them,
$$
q=20 \mathrm{C}
$$
\begin{aligned}
& U=\frac{q^2}{2 \mathrm{C}} \\
& 1.21 U=\frac{(q+2)^2}{2 \mathrm{C}}
\end{aligned}
$$
By solving them,
$$
q=20 \mathrm{C}
$$
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