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Question: Answered & Verified by Expert
If the chord of contact of the tangents from the point α,β to the circle x2+y2=r12 is a tangent to the circle x-a2+y-b2=r22, then
MathematicsCircleJEE Main
Options:
  • A r22α2+β2=r12-aα-bβ2
  • B r22α2+β2=r12+aα-bβ2
  • C r22α2+β2=r12-aα+bβ2
  • D r22α2+β2=r12+aα+bβ2
Solution:
1482 Upvotes Verified Answer
The correct answer is: r22α2+β2=r12-aα-bβ2
The equation of the chord of contact of tangents drawn from a point α,β to the circle x2+y2=r12 is
αx+βy=r12
This line touches the circle x-a2+y-b2=r22
aα+bβ-r12α2+β2=r2
r22α2+β2=aα+bβ-r122
r22α2+β2=r12-aα-bβ2

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