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Question: Answered & Verified by Expert
If the circles $x^2+y^2=a^2$ and $x^2+y^2-2 g x+g^2-b^2=0$ touch each other externally, then
MathematicsCircleJEE Main
Options:
  • A $g=a b$
  • B $g^2=a^2+b^2$
  • C $g^2=a b$
  • D $g=a+b$
Solution:
1749 Upvotes Verified Answer
The correct answer is: $g=a+b$
According to the condition, $\sqrt{(g-0)^2+(0-0)^2}=a+b \Rightarrow g=a+b$

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