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If the co-ordinate axes are the bisectors of the angles between the pair of lines $a x^2+2 h x y+b y^2=0$ where $h^2>a b$ and $a \neq b$, then
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Verified Answer
The correct answer is:
$h=0$
Equation of pair of bisectors of
$$
\begin{aligned}
& a x^2+2 h x y+b y^2=0 \text { is } \frac{x^2-y^2}{a-b}=\frac{x y}{h} \\
& \text { if } \quad h=0, x y=0 \\
& \Rightarrow \quad x=0, y=0
\end{aligned}
$$
Which are the equations of coordinate axes.
$$
\begin{aligned}
& a x^2+2 h x y+b y^2=0 \text { is } \frac{x^2-y^2}{a-b}=\frac{x y}{h} \\
& \text { if } \quad h=0, x y=0 \\
& \Rightarrow \quad x=0, y=0
\end{aligned}
$$
Which are the equations of coordinate axes.
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