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If the co-ordinates of the point in which the line joining the points $(3,5,-7)$ and $(-2,1,8)$ is intersected by the plane $y z$ is $\left[\mathrm{a}, \frac{13}{\mathrm{~b}}, \mathrm{c}\right]$, then $(a+b-c)=$
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The correct answer is:
3
3
Ratio $=-\left(\frac{3}{-2}\right)=\frac{3}{2}$
$\therefore \quad$ Required co-ordinates of the points are
$\begin{aligned}
& {\left[\frac{6-6}{5}, \frac{10+3}{5}, \frac{-14+24}{5}\right]=\left(0, \frac{13}{5}, 2\right) .} \\
& \therefore a+b-c=0+5-2=3
\end{aligned}$
$\therefore \quad$ Required co-ordinates of the points are
$\begin{aligned}
& {\left[\frac{6-6}{5}, \frac{10+3}{5}, \frac{-14+24}{5}\right]=\left(0, \frac{13}{5}, 2\right) .} \\
& \therefore a+b-c=0+5-2=3
\end{aligned}$
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