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If the current 3 A flowing in the primary coil is made zero in 0.1 sec, the emf induced in the secondary coil is 1.5 volt. The mutual inductance between the coils is
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The correct answer is:
0.05 H
Here: $e=1.5$ volt
$\Delta i=0-3=-3 \mathrm{~A}, \Delta t=0.1 \mathrm{sec}$
Now the emf induced in secondary coil
$e=\frac{M \Delta i}{\Delta t} \quad$ (numerically)
or $\quad 1.5=\frac{M \times 3}{0.1}$
or $\quad M=\frac{1.5 \times 0.1}{3}=0.05 \mathrm{H}$
$\Delta i=0-3=-3 \mathrm{~A}, \Delta t=0.1 \mathrm{sec}$
Now the emf induced in secondary coil
$e=\frac{M \Delta i}{\Delta t} \quad$ (numerically)
or $\quad 1.5=\frac{M \times 3}{0.1}$
or $\quad M=\frac{1.5 \times 0.1}{3}=0.05 \mathrm{H}$
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