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If the current through a resistor in a circuit increases by $3 \%$, the power dissipated by the resistor
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increases approximately by $6 \%$
$\mathrm{P=I^{2} R}$
$\mathrm{\frac{\Delta P}{P}=\frac{2 \Delta I}{I}=6 \%}$
$\mathrm{\frac{\Delta P}{P}=\frac{2 \Delta I}{I}=6 \%}$
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