Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
If the de Broglie wavelength of the electron in nth Bohr orbit in a hydrogenic atom is equal to 1.5 πa0 (a0 is Bohr radius), then the value of nz is:
ChemistryStructure of AtomJEE MainJEE Main 2019 (12 Jan Shift 2)
Options:
  • A 1.50
  • B 1.0
  • C 0.4
  • D 0.75
Solution:
1561 Upvotes Verified Answer
The correct answer is: 0.75
2πr=nλ

2πa0n2Z=nλ

2πa0n2Z=n ×1.5πa0

nZ=1.52=0.75

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.