Density of solution = $1.11 {\mathrm{gml}}^{-1}$

Molarity of solution = $2\mathrm{M}$

Density is the amount of $\mathrm{x} \mathrm{g}$ of solution in $1000\mathrm{ml}$ of solution.

Mass of solution = $\mathrm{density} \times \mathrm{volume}=1.11\times 1000=1110\mathrm{g}$

Molality is equal to the number of moles of solute present in $1000 \mathrm{g}$ of solution.

Number of moles of solute = $2 \mathrm{mole}$

Molar mass of ethylene glycol= $62 \mathrm{g}/\mathrm{mol}$

Mass of solute = $\mathrm{Mole}\times \mathrm{molar} \mathrm{mass}=2\times 62=124 \mathrm{g}$

Mass of the solvent = $1110-124=986\mathrm{g}$

$\mathrm{Molality}=\frac{\mathrm{Number} \mathrm{of} \mathrm{moles} \mathrm{of} \mathrm{solute}}{\mathrm{Mass} \mathrm{of} \mathrm{solvent} \mathrm{in} \mathrm{g}}\times 1000$

$\mathrm{Molality}=\frac{2}{986}\times 1000=2.02\mathrm{m}$

Hence, the molality of solution is $2.02 \mathrm{m}$(approx.)