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Question: Answered & Verified by Expert
If the dielectric constant of a substance is $K=\frac{4}{3}$, then the electric susceptibility $\psi_{\mathrm{e}}$ is
PhysicsElectrostaticsAP EAMCETAP EAMCET 2015
Options:
  • A $\frac{\varepsilon_0}{3}$
  • B $3\ \varepsilon_0$
  • C $\frac{4}{3} \varepsilon_0$
  • D $\frac{3}{4} \varepsilon_0$
Solution:
1578 Upvotes Verified Answer
The correct answer is: $\frac{\varepsilon_0}{3}$
The dielectric constant permittivity and susceptibility are relative as,
$\begin{aligned}
& K=1+\frac{\chi_e}{\varepsilon_0} \Rightarrow \frac{4}{3}=1+\frac{\chi_e}{\varepsilon_0} \\
& \Rightarrow \chi_e=\varepsilon_0\left(\frac{4}{3}-1\right) \\
& \Rightarrow \quad \chi_e=\frac{\varepsilon_0}{3}
\end{aligned}$
The electric susceptibility, $\chi_e=\frac{\varepsilon_0}{3}$

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