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If the dimensions of a physical quantity are given by $\left[\mathrm{L}^{\mathrm{a}} \mathrm{M}^{\mathrm{b}} \mathrm{T}^{c}\right]$ then the physical
quantity is
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quantity is
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Verified Answer
The correct answer is:
pressure if $a=-1, b=1, c=-2$
A. pressure if $a=1, b=-1, c=2$
Dimensions of velocity $=\left[\mathrm{M}^{0} \mathrm{~L}^{1} \mathrm{~T}^{-1}\right]$
Here, $a=0, b=1, c=-1$
Dimension of acceleration $=\left[\mathrm{M}^{0} \mathrm{~L}^{1} \mathrm{~T}^{-2}\right]$
Dimension of force $=\left[\mathrm{M}^{1} \mathrm{~L}^{1} \mathrm{~T}^{-2}\right]$
Dimension of pressure $=\left[\mathrm{M}^{1} \mathrm{~L}^{-1} \mathrm{~T}^{-2}\right.$
The physical quantity is pressure.
Dimensions of velocity $=\left[\mathrm{M}^{0} \mathrm{~L}^{1} \mathrm{~T}^{-1}\right]$
Here, $a=0, b=1, c=-1$
Dimension of acceleration $=\left[\mathrm{M}^{0} \mathrm{~L}^{1} \mathrm{~T}^{-2}\right]$
Dimension of force $=\left[\mathrm{M}^{1} \mathrm{~L}^{1} \mathrm{~T}^{-2}\right]$
Dimension of pressure $=\left[\mathrm{M}^{1} \mathrm{~L}^{-1} \mathrm{~T}^{-2}\right.$
The physical quantity is pressure.
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