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If the distance between the first maxima and fifth minima of a double slit pattern is $7 \mathrm{~mm}$ and the slits are separated by $0.15 \mathrm{~mm}$ with the screen 50 $\mathrm{cm} .$ from the slits, then the wavelength of the light used is:
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The correct answer is:
$600 \mathrm{nm}$
There are three and a half fringes from first maxima to fifth minima as shown.
$\Rightarrow \beta=\frac{7 \mathrm{~mm}}{3.5}=2 \mathrm{~mm} \Rightarrow \lambda=\frac{\beta \mathrm{D}}{\mathrm{d}}=600 \mathrm{nm}$
$\Rightarrow \beta=\frac{7 \mathrm{~mm}}{3.5}=2 \mathrm{~mm} \Rightarrow \lambda=\frac{\beta \mathrm{D}}{\mathrm{d}}=600 \mathrm{nm}$
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