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If the electron in a hydrogen atom jumps from an orbit with level $\mathrm{n}_1=2$ to an orbit with level $\mathrm{n}_2=1$ the emitted radiation has a wavelength given by
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The correct answer is:
$\lambda=4 / 3 \mathrm{R}$
$\frac{1}{\lambda}=R\left(\frac{1}{n_1^2}-\frac{1}{n_2^2}\right)=R\left(\frac{1}{1^2}-\frac{1}{2^2}\right)=\frac{3 R}{4}$
$\Rightarrow \lambda=\frac{4}{3 R}$
$\Rightarrow \lambda=\frac{4}{3 R}$
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