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Question: Answered & Verified by Expert
If the elevation in boiling point of a solution of $10 \mathrm{~g}$ of solute $(\mathrm{mol} . \mathrm{wt}=100)$ in $100 \mathrm{~g}$ of water is $\Delta T b$, the ebullioscopic constant of water is
ChemistrySolutionsBITSATBITSAT 2012
Options:
  • A $\frac{\Delta T_{b}}{10}$
  • B $\Delta T_{b}$
  • C $10 \Delta T_{b}$
  • D $100 \Delta T_{b}$
Solution:
1021 Upvotes Verified Answer
The correct answer is: $\Delta T_{b}$
$\mathrm{m}=\frac{1000 \times \mathrm{k}_{b} \times \mathrm{w}}{W \times \Delta T_{b}}$
or $\quad \begin{aligned} k_{\mathrm{b}} &=\frac{\mathrm{m} \times W \times \Delta T_{b}}{1000 \times \mathrm{w}}=\frac{100 \times 100 \times \Delta T_{b}}{1000 \times 10} \\ &=\Delta T_{b} \end{aligned}$

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