If the end correction of an open pipe is 0 . 8 cm then the inner radius of that pipe will be

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Question: Answered & Verified by Expert

If the end correction of an open pipe is

0.8 cm

then the inner radius of that pipe will be

PhysicsWaves and SoundNEET

Options:

A $\frac{1}{3} c m$
B $\frac{2}{3} c m$
C $\frac{3}{2} c m$
D $0.2 c m$

Solution:

2833 Upvotes Verified Answer

The correct answer is:

\frac{2}{3} c m

For open organ pipe

∆ L = 1.2 \times r

∴ r = ∆ L \times \frac{1}{1.2} = \frac{0.8}{1.2} = \frac{2}{3} c m .

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