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If the end correction of an open pipe is $0.8 \mathrm{~cm}$, then the inner radius of that pipe is
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Verified Answer
The correct answer is:
$\frac{2}{3} \mathrm{~cm}$
For an open pipe, $\mathrm{e}=0.6 \mathrm{~d}$
$\begin{aligned}
& \therefore \quad \mathrm{d}=\frac{\mathrm{e}}{0.6} \\
& \therefore \quad 2 \mathrm{r}=\frac{\mathrm{e}}{0.6} \\
& \therefore \quad \mathrm{r}=\frac{0.8}{1.2}=\frac{2}{3} \mathrm{~cm}
\end{aligned}$
$\begin{aligned}
& \therefore \quad \mathrm{d}=\frac{\mathrm{e}}{0.6} \\
& \therefore \quad 2 \mathrm{r}=\frac{\mathrm{e}}{0.6} \\
& \therefore \quad \mathrm{r}=\frac{0.8}{1.2}=\frac{2}{3} \mathrm{~cm}
\end{aligned}$
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