If the energy of photons corresponding to the wavelength of $ 6000 \mathrm{~A} $ is $ 3.2 \times 10^{-19} \mathrm{~J} $, the photon energy for a wavelength of $ 4000 Å $ will be

Question

If the energy of photons corresponding to the wavelength of $ 6000 \mathrm{~A} $ is $ 3.2 \times 10^{-19} \mathrm{~J} $, the photon energy for a wavelength of $ 4000 Å $ will be, $ 1.11 \times 10^{-19} \mathrm{~J} $, $ 2.22 \times 10^{-19} \mathrm{~J} $, $ 4.40 \times 10^{-19} \mathrm{~J} $, $ 4.80 \times 10^{-19} \mathrm{~J} $

MARKS App · Accepted Answer

Given for photons wavelength λ 1 = 6000 A ∘ and energy E 1 = 3 . 2 × 10 - 19 J and λ 2 = 4000 A ∘ , let energy for second photons is E 2 . We know energy of a photon is E = h c λ , then we can write E 2 E 1 = λ 1 λ 2 or E 2 = λ 1 λ 2 × E 1 , using given data, E 2 = 6000 4000 × 3 . 2 × 10 - 19 , on solving we get, E 2 = 4 .80 × 10 - 19 J

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