If the equation x 2 + a x + b = 0 has distinct real roots and x 2 + a x + b = 0 has only one real root, then

Question

If the equation x 2 + a x + b = 0 has distinct real roots and x 2 + a x + b = 0 has only one real root, then, b = 0 , a > 0, b > 0 , a 0, b > 0 , a > 0, b 0 , a > 0

MARKS App · Accepted Answer

Since the equation x 2 + a x + b = 0 has distinct real roots and x 2 + a x + b = 0 has only one real root So, one root of the equation x 2 + a x + b = 0 will be zero and the other root will be negative. Hence, b = 0 and a > 0

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