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If the error in the measurement of radius of a sphere is $2 \%$, then the error in the determination of volume of the sphere will be
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The correct answer is:
$6 \%$
$$
\frac{\Delta V}{V}=\frac{3 \Delta R}{R}
$$
\frac{\Delta V}{V}=\frac{3 \Delta R}{R}
$$
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