Search any question & find its solution
Question:
Answered & Verified by Expert
If the foot of the perpendicular drawn from the point $(1,0,-2)$ to the plane $\pi$ is $(2,0,-1)$ and the equation of the plane $\pi$ is $a x+b y+c z=2$ then $a^2+b^2+c^2=$
Options:
Solution:
1166 Upvotes
Verified Answer
The correct answer is:
8
$\begin{aligned} & \therefore \quad a=2, b=0, c=2 \\ & \therefore \quad a^2+b^2+c^2=4+0+4=8 .\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.