If the foot of the perpendicular drawn from the point $ (1,0,3) $ on a line passing through $ (\alpha, 7,1) $ is $ \left(\frac{5}{3}, \frac{7}{3}, \frac{17}{3}\right) $, then $ \alpha $ is equal to

Question

If the foot of the perpendicular drawn from the point $ (1,0,3) $ on a line passing through $ (\alpha, 7,1) $ is $ \left(\frac{5}{3}, \frac{7}{3}, \frac{17}{3}\right) $, then $ \alpha $ is equal to,

MARKS App · Accepted Answer

D . R . of B P = " open=" 5 3 - α , 7 3 - 7 , 17 3 - 1 D . R . of A P = " open=" 5 3 - 1 , 7 3 - 0 , 17 3 - 3 B P ⊥ A P ⇒ α = 4

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