Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
If the function fx=1-x2tanπx2 is continuous at x=1, then f1 is equal to
MathematicsContinuity and DifferentiabilityJEE Main
Options:
  • A 1π
  • B π2
  • C 0
  • D π
Solution:
2237 Upvotes Verified Answer
The correct answer is: 1π
f1=limx1fx=limx11-x2tanπx2
Put x=1+h
=limh01-1+h2tanπ21+h
=limh0-h2tanπ2+πh2
=limh0-h2-cotπh2
=limh0π2htanπh21π=1π

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.