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Question: Answered & Verified by Expert
If the function fx=ax+7;0x<2bx+5;x2 is differentiable x0, then 2a+4b is equal to
MathematicsContinuity and DifferentiabilityJEE Main
Options:
  • A 24016
  • B 5
  • C 8516
  • D 25016
Solution:
1377 Upvotes Verified Answer
The correct answer is: 5
fx must be continuous and differentiable at x=2
For continuity at x=2
f2-=f2+=f2
a2+7=b2+53a=2b+5i
For differentiability at x=2
f x = a 2 x+7 ; 0x<2 b ; x2
f 2 = f 2 +
a22+7=ba=6bii
From i18b=2b+5b=516
So, 2a+4b=12b+4b=16b=5

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