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Question: Answered & Verified by Expert
If the function  fx=x+a2 sin x0x<π42x cot x+b  π4xπ2a cos 2x-b sin x  π2<xπ is continuous in 0 π , then the values of a and b respectively are
MathematicsContinuity and DifferentiabilityJEE Main
Options:
  • A π6, -π12
  • B -π6π4
  • C -π3π12
  • D None of these
Solution:
2472 Upvotes Verified Answer
The correct answer is: π6, -π12
∵     f x  is continuous in 0 π  so it is continuous at x=π4  and  x=π2

∴    limxπ4-fx=limxπ4+fx

⇒    π4+a=π2+b          .....(1)

and     limxπ2-fx=limxπ2+fx

⇒    0 + b = - a - b                  .....(2)

By solving (1) and (2), we get, 

    a=π6b=-π12

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