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If the half cell reaction $A+e^{-} \rightarrow A^{-}$has a large negative reduction potential, it follows that
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$A^{-}$is readily oxidised
Since $E_{A / A^{-}}^o$ has large negative value, the tendency of $A$ to be reduced to $A^{-}$is very small. In other words tendency of $A^{-}$to be oxidized to $A$ is very large.
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