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If the image of an object is at the focal point $f$ to the right side of a convex lens, the position of the object on the left of the lens is at
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Verified Answer
The correct answer is:
$\infty$
The given situation is shown in the following figure
Given, $\quad v=+f, f=+f$
By
$\frac{1}{v}-\frac{1}{u}=\frac{1}{f}$
We have, $\frac{1}{f}-\frac{1}{f}=\frac{1}{u} \Rightarrow \frac{1}{u}=0 \Rightarrow u=\infty$
So, object is at $\infty$ distance on right side of lens.
Given, $\quad v=+f, f=+f$
By
$\frac{1}{v}-\frac{1}{u}=\frac{1}{f}$
We have, $\frac{1}{f}-\frac{1}{f}=\frac{1}{u} \Rightarrow \frac{1}{u}=0 \Rightarrow u=\infty$
So, object is at $\infty$ distance on right side of lens.
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