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Question: Answered & Verified by Expert
If the integral Ι=esinxcosxx2+2xdx=efxgx+C (where, C is the constant of integration), then the number of solution(s) of fx=gx is/are
MathematicsIndefinite IntegrationJEE Main
Options:
  • A 0
  • B 2
  • C 4
  • D 6
Solution:
1246 Upvotes Verified Answer
The correct answer is: 2
As,  Ι= e f x f x g x + g x dx= e f x g x +C
Thus, esinxcosxx2+2xdx=esinxx2+C
i.e. fx=sinx & gx=x2

Which intersect at 2 points.

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