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If the $K . E$. of a body is increased by $300 \%$, its momentum will increase by
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100%
Let initial kinetic energy, $E_1=E$ Final kinetic energy, $E_2=E+300 \%$ of $E=4 E$
$\begin{aligned} & \text { As } P \propto \sqrt{E} \Rightarrow \frac{P_2}{P_1}=\sqrt{\frac{E_2}{E_1}}=\sqrt{\frac{4 E}{E}}=2 \\ & \Rightarrow P_2=P_1+100 \% \text { of } P_1\end{aligned} \Rightarrow P_2=2 P_1$
i.e. Momentum will increase by $100 \%$.
$\begin{aligned} & \text { As } P \propto \sqrt{E} \Rightarrow \frac{P_2}{P_1}=\sqrt{\frac{E_2}{E_1}}=\sqrt{\frac{4 E}{E}}=2 \\ & \Rightarrow P_2=P_1+100 \% \text { of } P_1\end{aligned} \Rightarrow P_2=2 P_1$
i.e. Momentum will increase by $100 \%$.
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