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If the kinetic energy in $\mathrm{J}$, of $\mathrm{CH}_4$ (molar mass $=16 \mathrm{~g} \mathrm{~mol}^{-1}$ ) at $T(\mathrm{~K})$ is $X$, the kinetic energy in $\mathrm{J}$, of $\mathrm{O}_2$ (molar mass $=32 \mathrm{~g} \mathrm{~mol}^{-1}$ ) at the same temperature is
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2557 Upvotes
Verified Answer
The correct answer is:
$x$
At same temperature, kinetic energy of both the gases will be same. In short
$$
\begin{array}{lc}
\because & \mathrm{KE} \propto \sqrt{T} \\
\therefore & \mathrm{KE}_{\left(\mathrm{CH}_4\right)}=\mathrm{KE}_{\left(\mathrm{O}_2\right)}=X
\end{array}
$$
(for all gases)
$$
\begin{array}{lc}
\because & \mathrm{KE} \propto \sqrt{T} \\
\therefore & \mathrm{KE}_{\left(\mathrm{CH}_4\right)}=\mathrm{KE}_{\left(\mathrm{O}_2\right)}=X
\end{array}
$$
(for all gases)
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