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If the kinetic energy of a body changes by $20 \%$ then its momentum would change by -
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$\frac{\frac{p_f^2}{2 m}-\frac{p_i^2}{2 m}}{\frac{p_i^2}{2 m}} \times 100=20$
$\Rightarrow \frac{p_f}{p_i}=\sqrt{1.2}=1.095 \Rightarrow \frac{p_f-p_i}{p_i}=0.095$
Therefore $\%$ increase $=9.5 \%$
$\Rightarrow \frac{p_f}{p_i}=\sqrt{1.2}=1.095 \Rightarrow \frac{p_f-p_i}{p_i}=0.095$
Therefore $\%$ increase $=9.5 \%$
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