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If the lattice parameter for a crystalline structure is $3.6 \%$, then the atomic radius in fcc crystal is
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1485 Upvotes
Verified Answer
The correct answer is:
$1.27 \&$
$$
2 R=\frac{a}{\sqrt{2}}
$$
$$
\therefore R=\frac{a}{2 \sqrt{2}}
$$
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