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Question: Answered & Verified by Expert
If the length and breadth of a rectangle of maximum area that can be inscribed in an ellipse x2a2+y2b2=1 are 82 and 42 respectively, then the eccentricity of that ellipse is
MathematicsEllipseTS EAMCETTS EAMCET 2021 (05 Aug Shift 1)
Options:
  • A 12
  • B 32
  • C 14
  • D 13
Solution:
1438 Upvotes Verified Answer
The correct answer is: 32

Ellipse x2a2+y2b2=1

 Coordinates of vertices of a rectangle inscribed in ellipse are +acosθ,+bsinθ

Area of Rectangle =2acosθ2bsinθ

=2absin2θ square units.

For area to be maximum sin2θ=1

θ=π4

Length =2acosθ=82 unit

Breadth =2bsinθ=42 unit

ab=2

Eccentricity, e=1-b2a2

e=1-14=32

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