Search any question & find its solution
Question:
Answered & Verified by Expert
If the length of a closed organ pipe is $1.5 \mathrm{~m}$ and velocity of sound is $330 \mathrm{~m} / \mathrm{s}$, then the frequency for the second note is
Options:
Solution:
2862 Upvotes
Verified Answer
The correct answer is:
165 HZ
For closed pipe second note $=3 \mathrm{v} 41=3 \times 3304 \times 4.5=165 \mathrm{~Hz}$.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.