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Question: Answered & Verified by Expert
If the length of a closed organ pipe is $1.5 \mathrm{~m}$ and velocity of sound is $330 \mathrm{~m} / \mathrm{s}$, then the frequency for the second note is
PhysicsWaves and SoundJEE Main
Options:
  • A 220 Hz
  • B 165 HZ
  • C 110 Hz
  • D 55 Hz
Solution:
2862 Upvotes Verified Answer
The correct answer is: 165 HZ
For closed pipe second note $=3 \mathrm{v} 41=3 \times 3304 \times 4.5=165 \mathrm{~Hz}$.

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