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If the length of perpendicular drawn from origin on a plane is 7 units and its direction ratios are $-3,2,6$, then that plane is
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Verified Answer
The correct answer is:
$-3 x+2 y+6 z-49=0$
Equation of a plane, when direction ratio and length of perpendicular is given, $a x+b y+c z=p \sqrt{a^2+b^2+c^2}$
Given, $(a, b, c) \rightarrow(-3,2,6)$
$\begin{aligned}
& -3 x+2 y+6 z=7 \sqrt{(-3)^2+2^2+6^2} \\
& -3 x+2 y+6 z=49
\end{aligned}$
Given, $(a, b, c) \rightarrow(-3,2,6)$
$\begin{aligned}
& -3 x+2 y+6 z=7 \sqrt{(-3)^2+2^2+6^2} \\
& -3 x+2 y+6 z=49
\end{aligned}$
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