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If the line $\mathbf{r}=\mathbf{a}+t \mathbf{b}$ is parallel to the plane $\mathbf{r}=\mathbf{c}+l \mathbf{d}+m \mathbf{e}$, then
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Verified Answer
The correct answer is:
$[\mathrm{bde}]=0$
We have,
Line $\mathbf{r}=\mathbf{a}+\mathbf{l} \mathbf{b}$ is paralleI to the plane
$\mathbf{r}=\mathbf{c}+l \mathbf{d}+m \mathbf{e}$
$\therefore$ Normal vector of plane are $(\mathrm{d} \times \mathbf{e})$.
Since, line and plane are parallel.
Line $\mathbf{r}=\mathbf{a}+\mathbf{l} \mathbf{b}$ is paralleI to the plane
$\mathbf{r}=\mathbf{c}+l \mathbf{d}+m \mathbf{e}$
$\therefore$ Normal vector of plane are $(\mathrm{d} \times \mathbf{e})$.
Since, line and plane are parallel.
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