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Question: Answered & Verified by Expert
If the line x+y+1=0 intersects the circle x2+y2+x+3y=0 at two points A and B, then the centre of the circle which passes through the points A, B and the point of intersection of the tangents drawn at A and B to the given circle is
MathematicsCircleTS EAMCETTS EAMCET 2019 (03 May Shift 2)
Options:
  • A 58,58
  • B (1,-1)
  • C 34,-14
  • D (3,-4)
Solution:
1119 Upvotes Verified Answer
The correct answer is: 34,-14

x2+y2+x+3y=0

Ab:x+y+1=0 is chord of contact from intersection point h,k

AB;  xh+yk+x+h2+3(y+k2)=0

x(h+12)+y(k+32)+h2+3k2=0

On comparing

h+121=k+321=h2+3k21

h+12=k+32

h-k=1  ...(1)

h+12=h2+3k2

h2-3k2=-12

h-3k=-1  ...(2)

1, 2

2k=2k=1, h=2

Circle passing through A & B is

x2+y2+x+3y+(x+y+1)=0

It passes through (2,1)

4+1+2+3+(4)=0

=-52

x2+y2-3x2+y2-52=0

Centre (34, -14)

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