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Question: Answered & Verified by Expert
If the line $y=m x+c$ touches the ellipse $\frac{x^2}{b^2}+\frac{y^2}{a^2}=1$, then $c=$
MathematicsEllipseJEE Main
Options:
  • A $\pm \sqrt{b^2 m^2+a^2}$
  • B $\pm \sqrt{a^2 m^2+b^2}$
  • C $\pm \sqrt{b^2 m^2-a^2}$
  • D $\pm \sqrt{a^2 m^2-b^2}$
Solution:
2986 Upvotes Verified Answer
The correct answer is: $\pm \sqrt{b^2 m^2+a^2}$
Since, here $a$ and $b$ are interchanged, So, \(c= \pm \sqrt{b^2 m^2+a^2}\)

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