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Question: Answered & Verified by Expert
If the lines $a x+b y+c=0, b x+c y+a=0$ and $c x+a y+b=0$ be concurrent, then
MathematicsStraight LinesJEE Main
Options:
  • A $a^3+b^3+c^3+3 a b c=0$
  • B $a^3+b^3+c^3-a b c=0$
  • C $a^3+b^3+c^3-3 a b c=0$
  • D None of these
Solution:
1978 Upvotes Verified Answer
The correct answer is: $a^3+b^3+c^3-3 a b c=0$
Here the given lines are
$\begin{aligned}
& a x+b y+c=0 \\
& b x+c y+a=0 \\
& c x+a y+b=0
\end{aligned}$

The lines will be concurrent, if
$\begin{aligned}
& \qquad\left|\begin{array}{lll}
a & b & c \\
b & c & a \\
c & a & b
\end{array}\right|=0 \\
& \Rightarrow a^3+b^3+c^3-3 a b c=0 .
\end{aligned}$

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