If the map distance between genes P and Q is 4 units, between P and R is 11 units, and between Q and R is 7 units, the order of genes on the linkage map can be traced as follows:

Question

If the map distance between genes P and Q is 4 units, between P and R is 11 units, and between Q and R is 7 units, the order of genes on the linkage map can be traced as follows:, , , ,

MARKS App · Accepted Answer

Genes P, Q and R are linked, thus present on the same chromosome. P gene and R gene are farthest from each other having a distance of 11 units where as P gene and Q gene are closest with just 4 units and Q is 7 units away from R. Hence, Q gene is present between P and R and the map is as follows -

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