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If the mass defect of a nuclide is $3.32 \times 10^{-26} \mathrm{~g}$, its binding energy is $\mathrm{MeV}$
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Verified Answer
The correct answer is:
18.62
Mass defect $=3.32 \times 10^{-26} \mathrm{~g}$
$=\frac{3.32 \times 10^{-26}}{1.66 \times 10^{-24}} \mathrm{amu}$
Binding energy $=$ Mass defect $\times 931 \mathrm{MeV}$
$=\frac{3.32 \times 10^{-26}}{1.66 \times 10^{-24}} \times 931=18.62 \mathrm{MeV}$
$=\frac{3.32 \times 10^{-26}}{1.66 \times 10^{-24}} \mathrm{amu}$
Binding energy $=$ Mass defect $\times 931 \mathrm{MeV}$
$=\frac{3.32 \times 10^{-26}}{1.66 \times 10^{-24}} \times 931=18.62 \mathrm{MeV}$
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