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If the matrices $A=\left[\begin{array}{lll}2 & 1 & 3 \\ 4 & 1 & 0\end{array}\right]$ and $B=\left[\begin{array}{rr}1 & -1 \\ 0 & 2 \\ 5 & 0\end{array}\right]$, then $\mathrm{AB}$ will be
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2685 Upvotes
Verified Answer
The correct answer is:
$\left[\begin{array}{cr}17 & 0 \\ 4 & -2\end{array}\right]$
$$
\text { Hints : } \mathrm{AB}=\left[\begin{array}{lll}
2 & 1 & 3 \\
4 & 1 & 0
\end{array}\right]\left[\begin{array}{rr}
1 & -1 \\
0 & 2 \\
5 & 0
\end{array}\right]=\left[\begin{array}{lr}
17 & 0 \\
4 & -2
\end{array}\right]
$$
\text { Hints : } \mathrm{AB}=\left[\begin{array}{lll}
2 & 1 & 3 \\
4 & 1 & 0
\end{array}\right]\left[\begin{array}{rr}
1 & -1 \\
0 & 2 \\
5 & 0
\end{array}\right]=\left[\begin{array}{lr}
17 & 0 \\
4 & -2
\end{array}\right]
$$
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